struct.error
PythonERRORNotableValue ErrorHIGH confidence
Binary struct pack/unpack failed
Production Risk
Common when parsing network protocols; always validate buffer length with struct.calcsize().
What this means
Raised by the struct module when a pack format string does not match the data, or when trying to unpack a buffer of the wrong size.
Why it happens
- 1Unpacking a buffer that is shorter than the format requires
- 2struct.pack() value out of range for the format (e.g., >255 for "B")
- 3Wrong format string for the binary data being parsed
How to reproduce
Unpacking a buffer shorter than the format requires.
trigger — this will error
trigger — this will error
import struct
struct.unpack('>IH', b'\x00\x01') # Format needs 6 bytes, only 2 givenexpected output
struct.error: unpack requires a buffer of 6 bytes
Fix
Check buffer length before unpacking
WHEN Parsing binary data from network or files
Check buffer length before unpacking
import struct
FORMAT = '>IHB' # 4+2+1 = 7 bytes
SIZE = struct.calcsize(FORMAT)
def parse_packet(data):
if len(data) < SIZE:
raise ValueError(f"Packet too short: {len(data)} < {SIZE}")
return struct.unpack(FORMAT, data[:SIZE])Why this works
struct.calcsize() returns the exact byte count needed; always validate before unpack.
Code examples
Triggerpython
import struct
struct.unpack(">IH", b"\x00\x01") # struct.error: unpack requires 6 bytes, got 2Handle with try/exceptpython
import struct
FMT = ">IH"
try:
vals = struct.unpack(FMT, data)
except struct.error as e:
print(f"Bad binary data: {e}")Avoid with calcsize checkpython
import struct
FMT = ">IH"
SIZE = struct.calcsize(FMT)
if len(data) >= SIZE:
vals = struct.unpack(FMT, data[:SIZE])Same error in other languages
Sources
Official documentation ↗
Python Docs — struct module
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